Find the value 3log2-1-3log27-log 12 -log4-3log5

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Logarithms

Find the valu...

Question

Find the value

$3 l o g 2 - \frac{1}{3} l o g 27 + l o g 12 - l o g 4 + 3 l o g 5$

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Solution

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3 log 2 + \frac{1}{3} log 27 - log 4 = log x

{log}_{4} \sqrt[3]{8^{(3 + \frac{1}{3} {log}_{2} x)}} = 0

2 log 3 + 3 log 2 + log 5 - log 12

log 4 = 0.602

log 27 = 1.431

log 12

1.0 k 9

k

k

\frac{1}{2} log 9 + 2 log 6 + \frac{1}{4} log 81 - log 12

log 3

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