Find the value of √10+√25+√108+√154+√225+(√225729−√25144)÷√1681
A
313
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B
547
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C
10813
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D
6916
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Solution
The correct option is D6916 √10+√25+√108+√154+√225+(√225729−√25144)÷√1681=√10+√25+√108+√154+15+(1527−512)÷49=√10+√25+√108+√169+(59−512)÷49=√10+√25+√108+13+(20−1536)÷49=√10+√25+√121+(536)÷49=√10+√25+11+536÷49=√10+√36+536×94=√10+6+516=√16+516=4+516=6916