Find the value of -10m2n2-20 mn15 for m-1-2 and n-1-

( 10m^2n^2) ×( 20mn^15) = 200m^3n^17 = 200( 1.2)^3( 1)^17 = 200 × 12 × 12 × 1210 × 10 × 10 = #160; 345610 = #160 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Exponents with Unlike Bases and Same Exponent

Find the valu...

Question

Find the value of $(- 10 m^{2} n^{2}) \times (- 20 m n^{15})$ for $m = 1.2$ and $n = - 1$ .

Open in App

Solution

Suggest Corrections

Similar questions

m = 3

n = 2

2 m^{2} n^{2}

m = \sqrt[3]{15}

n = \sqrt[3]{14}

m - n - \frac{1}{m^{2} + m n + n^{2}}

m \in N

m = \frac{n^{2} - n - 35}{n - 4}

m = \frac{1}{3 - \sqrt{8}}

n = \frac{1}{3 + \sqrt{8}}

n^{2}

17 - 6 \sqrt{m}

Question 67 (b)

Find the value of the given polynomial at m = 1, n = -1 and p = 2

$m^{2} + n^{2} + p^{2}$

Join BYJU'S Learning Program