Find the value of $16 x^{2} + 25 y^{2} + 40 x y$ , when $x = 3, y = 6$

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Solution

Given $16 x^{2} + 25 y^{2} + 40 x y$

Simply put $x = 3$ & $y = 6$ in given expression

Hence $16 (9) + 25 (36) + 40 (3 \times 6) = 1144 + 900 + 720 = 1764$

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