CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the value of 22.927.12 using a suitable algebraic identity.

A
500
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
474
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
497
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
574
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 474
Given, 22.927.12.
It is in the form of a2b2, where a = 22.9 and b = 7.1

Using the identity, a2b2=(a+b)(ab),
we get

22.927.12

=(22.9+7.1)(22.97.1)

=(30)(15.8)

=474

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon