Find the value of $^{'} a^{'}$ using the suitable algebraic identity, if $10 a = 60^{2} - 40^{2}$ .
200

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Solution

The correct option is A 200
Here,
$60^{2} - 40^{2}$ can be written in the algebraic form $x^{2} - y^{2} = (x + y) \times (x - y)$
$60^{2} - 40^{2} = (60 + 40) \times (60 - 40$ )
$60^{2} - 40^{2} = 100 \times 20$
$60^{2} - 40^{2} = 2000$
Now,
$10 a = 2000$
$a = \frac{2000}{10}$
$a = 200$

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