Question

Find the value of $(-2x^2)\times (-3y^2)\times (-6z^2)$.

• A. $-36xyz$
• B. $36xyz$
• C. $-36x^2{y}^{2}z$
• D. $-36x^2{y}^2{z}^2$

Answer 1

The correct option is D $-36x^2{y}^2{z}^2$

$-2x^2\times -3y^2\times -6z^2$
$=-2\times -3\times -6\times x^2\times y^2\times z^2$
$=-36x^2{y}^2{z}^2$