Question

Find the value of ($3^0$ + $4^{-1}$) × $2^2$. ___

Answer 1

In ($3^0$ + $4^{-1}$) × $2^2$,

$(1+4^{-1})\times 2^2$,

Since $4^{-1}$ = $\frac{1}{4}$,

(1 + $\frac{1}{4})$ × $2^2$

$\frac{5}{4}\times 4$

= 5