Find the value of (3a−12)(3a−12).
9a2−2a+14
6a2−3a+14
9a2−3a+14
9a2−3a+12
(3a−12)(3a−12)=(3a−12)2 Using the identity (a−b)2=a2−2ab+b2, (3a−12)2=(3a)2−2×3a×12+(12)2=9a2−3a+14
Find the value of : (3a−12)(3a−12)
Evaluate : (3a−12)(3a−12)
Factorise:
9a2+19a2−2−12a+43a