Find the value of 3 a -1-23 a -1-2-A- 9 a 2-2 a -1-4- 6 a 2-3 a -C- 9 a2-3 a-D- 9 a 2-3 a -1-2

The correct option is C 9a^2 3a+1/4 (3a 1/2)(3a 1/2) =(3a 1/2)^2 Using the identity nbsp; (a b)^2=a^2 2ab+b^2, (3a 1/2)^2 =(3a)^2 2× 3a×1/2+(1/2)^2 =9a^ ...

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Byju's Answer

Standard IX

Mathematics

Polynomial Expressions

Find the valu...

Question

Find the value of $(3 a - \frac{1}{2}) (3 a - \frac{1}{2})$ .

$9 a^{2} - 2 a + \frac{1}{4}$

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$6 a^{2} - 3 a + \frac{1}{4}$

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$9 a^{2} - 3 a + \frac{1}{4}$

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$9 a^{2} - 3 a + \frac{1}{2}$

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Solution

The correct option is C
$9 a^{2} - 3 a + \frac{1}{4}$

$(3 a - \frac{1}{2}) (3 a - \frac{1}{2}) = (3 a - \frac{1}{2})^{2}$

Using the identity
$(a - b)^{2} = a^{2} - 2 a b + b^{2}$ ,

$(3 a - \frac{1}{2})^{2} = (3 a)^{2} - 2 \times 3 a \times \frac{1}{2} + (\frac{1}{2})^{2} = 9 a^{2} - 3 a + \frac{1}{4}$

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Similar questions

Q. Evaluate :

(3 a - \frac{1}{2}) (3 a - \frac{1}{2})

Find the value of : $(3 a - \frac{1}{2}) (3 a - \frac{1}{2})$

Evaluate : $(3 a - \frac{1}{2}) (3 a - \frac{1}{2})$

Q. Subtract

- 5 a^{2} - 2 a + 1

from the sum of

4 a^{2} + 3 - 7 a

and

8 a - 7

Factorise:

$9 a^{2} + \frac{1}{9 a^{2}} - 2 - 12 a + \frac{4}{3 a}$

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Find the value of (3a−12)(3a−12).

The correct option is C 9a2−3a+14 (3a−12)(3a−12)=(3a−12)2 Using the identity (a−b)2=a2−2ab+b2, (3a−12)2=(3a)2−2×3a×12+(12)2=9a2−3a+14

Find the value of $(3 a - \frac{1}{2}) (3 a - \frac{1}{2})$ .