Find the value of 3 a -1-23 a -1-2-A- 9 a 2-3 a -1-4- 6 a 2-3 a -C- 6 a 2-3 a -D- 9 a 2-2 a -I-4

The correct option is A 9a^2 3a+1/4 (3a 1/2)(3a 1/2) =(3a 1/2)^2 It is in the form of nbsp;(x y)^2, nbsp; where, x = 3a and y = 1/2 Using the identity ...

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Byju's Answer

Standard VIII

Mathematics

Deducing Formula for (x-y)^2

Find the valu...

Question

Find the value of $(3 a - \frac{1}{2}) (3 a - \frac{1}{2})$ .

6 a^{2} - 3 a + \frac{1}{2}

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9 a^{2} - 3 a + \frac{1}{4}

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6 a^{2} - 3 a + \frac{1}{4}

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9 a^{2} - 2 a + \frac{1}{4}

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Solution

The correct option is B $9 a^{2} - 3 a + \frac{1}{4}$
$(3 a - \frac{1}{2}) (3 a - \frac{1}{2}) = (3 a - \frac{1}{2})^{2}$

It is in the form of $(x - y)^{2}$ ,
where, x = 3a and y = $\frac{1}{2}$

Using the identity
$(x - y)^{2} = x^{2} - 2 x y + y^{2}$ ,

$(3 a - \frac{1}{2})^{2} = (3 a)^{2} - 2 \times 3 a \times \frac{1}{2} + (\frac{1}{2})^{2} = 9 a^{2} - 3 a + \frac{1}{4}$

Therefore, the value of $(3 a - \frac{1}{2}) (3 a - \frac{1}{2})$ is $9 a^{2} - 3 a + \frac{1}{4}$

Suggest Corrections

Find the value of (3a−12)(3a−12).

The correct option is B 9a2−3a+14 (3a−12)(3a−12)=(3a−12)2 It is in the form of (x−y)2, where, x = 3a and y = 12 Using the identity (x−y)2=x2−2xy+y2, (3a−12)2=(3a)2−2×3a×12+(12)2=9a2−3a+14 Therefore, the value of (3a−12)(3a−12) is 9a2−3a+14

Find the value of $(3 a - \frac{1}{2}) (3 a - \frac{1}{2})$ .