Question

Find the value of : $4{\cot }^2{45}^{\circ }+{\sec }^2{60}^{\circ }+cose{c}^2{30}^{\circ }+\cot {90}^{\circ }$

Answer 1

$4{\cot }^{2}45+{\sec }^{2}60+{cosec}^{2}30+\cot 90$

$\frac{4}{{\tan }^{2}45}+\frac{1}{{\cos }^{2}60}+\frac{1}{{\sin }^{2}30}+\frac{1}{\tan 90}$

$4+2^2+2^2+0$

$=4+4+4$

$=12$