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Question

Find the value of 97×103 using a suitable algebraic identity.

A
9999
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B
1111
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C
9991
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D
8999
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Solution

The correct option is C 9991
97×103 can be rewritten as (1003)(100+3).

We know, (a+b)(ab)=a2b2.

97×103=(100)2(3)2

=100009

=9991

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