Find the value of $a_{30} - a_{20}$ for the A.P $4, 7, 10, . . . .$

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Solution

Given the first term of the A.P. is $4$ and common difference is $3$ .
Now, $a_{20} = 4 + (20 - 1) 3 = 61$ and $a_{30} = 4 + (30 - 1) 3 = 91$ .
Then $a_{30} - a_{20} = 91 - 61 = 30$

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