Question

Find the value of A and B. (Here, A $\ne$ 0 and B $\ne$ 0)

$\begin{array}{c}AB\\ AB\\ +B\\ BB\end{array}$

• A. A = 1 , B = 3
• B. A = 5, B = 2
• C. A = 2 , B = 5
• D. A = 3 , B = 1

Answer 1

The correct option is C A = 2 , B = 5

B + B + B = B → on adding B three times, we are getting B again in the units place. This is only possible if B is either 0 or 5.

0 + 0 + 0 = 0 (this will give A = 0 and B = 0) and 5 + 5 + 5 = 15; and 1 is carried over.
It is given that A $\ne$ 0 and B $\ne$ 0.
$\therefore$ B = 5

Now, we have

1 + A + A = 5

2A = 4

A = 2

Let's verify

$\begin{array}{c}25\\ 25\\ +5\\ 55\end{array}$