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Question

Find the value of a and b if [a+3b2+206]=[2a+13b0b25b].

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Solution

Comparing both sides
a+3=2a+1
a2a=13
a=2
b2+2=3bb23b+2=0b22bb+2=0b(b2)1(b2)=0(b1)(b2)=0b=1,2
Also 6=b25b
b25b+6=0b23b2b+6=0b(b3)2(b3)=0(b2)(b3)=0b=2,3a=2,b=2

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