Question

Find the value of A and B in the following sum:
$3B$
$\underset{–}{\times A}$
$\underset{–}{252}$

• A. $B=6,A=7$
• B. $B=4,A=3$
• C. $B=3,A=4$
• D. $B=7,A=6$

Answer 1

The correct option is A $B=6,A=7$

Now as $A\times B$ gives 2 in the product, the combinations could be
$2\times 1$ or $1\times 2,6\times 2$ or $2\times 6,3\times 4$
or $4\times 3,6\times 7$ or $7\times 6$ or $8\times 4$ or
$4\times 8,9\times 8$ or $8\times 9$. But to get 2 in hundred's
place and 5 in ten's place in the product, B has to be 6 and A has to be
7. Then $6\times 7=42$.
Write 2 and carry over 4. then $7\times 3=21$ and add 4 to get 2 and 5 in the product.
The value of B is 6 and A is 7.