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Question

Find the value of a for which the equation 2x+ay=5 has (1,1) as a solution, find two more solution for the equation obtained.

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Solution

2x+ay=5 has (1,1) as its solution
2×1+a(1)=52a=5a=32x3y=5
other solutions are (10,5) and (25,15)
2×103×5=2015=5
and 2×253×15=5045=5

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