Question

Find the value of a, so that the point (3,a) lie on the line 2x-3y=5.

Answer 1

Since (3,a) lie on the line 2x - 3y = 5 ...(1)

Substituting x=3 and y=a in (1) we get

2(3) - 3(a) = 5

6 - 3a = 5

$\Rightarrow 3a=1$

$\Rightarrow a=1/3$.