Find the value of ′a′ using the suitable algebraic identity, if 10a=602−402.
200
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Solution
The correct option is A 200 Here, 602−402 can be written in the algebraic form x2−y2=(x+y)×(x−y) 602−402=(60+40)×(60−40) 602−402=100×20 602−402=2000
Now, 10a=2000 a=200010 a=200