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Byju's Answer
Standard XII
Mathematics
Derivative Operator dy/dx
Find the valu...
Question
Find the value of
cos
(
3
π
2
+
n
)
cos
(
2
π
+
n
)
[
cot
(
3
π
2
−
n
)
+
cot
(
2
π
+
n
)
]
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Solution
Given expression can be rewritten as
⇒
sin
(
n
)
cos
(
n
)
[
tan
(
n
)
+
cot
n
]
⇒
sin
n
cos
n
[
sin
n
cos
n
+
cos
n
sin
n
]
⇒
sin
n
cos
n
[
sin
2
n
+
cos
2
n
sin
n
cos
n
]
⇒
[
sin
2
n
+
cos
2
n
]
=
+
1
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0
Similar questions
Q.
The value of
cos
(
3
π
2
+
θ
)
cos
(
2
π
+
θ
)
[
cot
(
3
π
2
−
θ
)
+
cot
(
2
π
+
θ
)
]
is
Q.
Find the value of x:
cos
(
3
π
2
+
x
)
cos
(
2
π
+
x
)
[
cot
(
3
π
2
−
x
)
+
cot
(
2
π
+
x
)
]
=
1
Q.
Find the value of
cos
(
3
π
2
+
x
)
cos
(
2
π
+
x
)
[
cot
(
3
π
2
−
x
)
+
cot
(
2
π
+
x
)
]
.
Given,
sin
2
x
+
cos
2
x
=
1
Q.
cos
(
3
π
2
+
x
)
cos
(
2
π
+
x
)
[
cot
(
3
π
2
−
x
)
+
cot
(
2
π
+
x
)
]
=
1
Q.
cos{3π/2 + x } cos(2π+x) [ cot {3π/2 - z} + cot (2π+x) ] =1
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