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Question

Find the value of cos(3π2+n)cos(2π+n)[cot(3π2n)+cot(2π+n)]

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Solution

Given expression can be rewritten as
sin(n)cos(n)[tan(n)+cotn]
sinncosn[sinncosn+cosnsinn]
sinncosn[sin2n+cos2nsinncosn]
[sin2n+cos2n]
=+1

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