Question

Find the value of $\frac{1}{y}+\frac{1}{2y}+\frac{1}{3y}$, if $y\ne 0$

• A. $\frac{1}{2y}$
• B. $\frac{1}{6y}$
• C. $\frac{5}{6y}$
• D. $\frac{11}{6y}$
• E. $\frac{1}{6y^3}$

Answer 1

The correct option is D $\frac{11}{6y}$

The value of $\frac{1}{y}+\frac{1}{2y}+\frac{1}{3y}$

$=\frac{6+3+2}{6y}$

$=\frac{11}{6y}$