Question

If $\frac{1}{4}x+2y=\frac{11}{4}$ and $-6y-x=7$, then the value of half of $y$ is.

• A. $\frac{11}{2}$
• B. $\frac{9}{2}$
• C. $-\frac{61}{2}$
• D. $\frac{83}{2}$

Answer 1

Answer: (B)

$\frac{9}{2}$

Given, $\frac{x}{4}+2y=\frac{11}{4}$ $\Rightarrow x+8y=11$

Adding both the equation:

$\Rightarrow 2y=18$

$\Rightarrow y=9$

Hence, the required value of $y$ is $9$.

Therefore half the value of $y$ is $4.5$ or $\frac{9}{2}$.