Question

Find the value of $\frac{3x-1}{4}+\frac{x+3}{6}+\frac{2x-1}{3}=0$

Answer 1

given, $\frac{3x-1}{4}+\frac{x+3}{6}+\frac{2x-1}{3}=0$

$\frac{3x-1}{4}+\frac{x+3}{6}+\frac{2(2x-1)}{6}=0$

$\Rightarrow \frac{3x-1}{4}+\frac{x+3+4x-2}{6}=0$

$\Rightarrow \frac{3x-1}{4}+\frac{5x+1}{6}=0$

$\Rightarrow \frac{6(3x-1)}{24}+\frac{4(5x+1)}{24}=0$

$\Rightarrow \frac{18x-6}{24}+\frac{20x+4}{24}=0$

$\Rightarrow \frac{18x-6+20x+4}{24}=0$

$\Rightarrow \frac{38x-2}{24}=0$

$\Rightarrow 38x-2=0$

$\Rightarrow x=\frac{2}{38}=\frac{1}{19}$