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Question

Solve : 43x5+7x3+413=0 Hence find the value of 'p' if 3p2x+1=0


Solution

 43x5+7x3+413=0 43x5+7x3+133=0129x+355x+65=015  (L.C.M. of 5, 3, 3 = 15)14x+112=0 14x=112 x=11214=8Hence x = 8Now ,3p2x+1=0 3p2×8+1=0 3p16+1=0 3p15=0 3p=15 p=153=5 x=8,p=5


Mathematics
Concise Mathematics
Standard VIII

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