Find the value of 4y - 4 given that 4y - 4 - 20y - 20

The correct option is A 0 The value of 20/y+20=5 ( 4/y+4 ) Given 4/y+4=5 ( 4/y+4 ) Given one is possible only when the value of #160; 4/ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Reducing Equations to Simpler Form

Find the valu...

Question

Find the value of $\frac{4}{y} + 4$ given that $\frac{4}{y} + 4 = \frac{20}{y} + 20$

- 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $0$
The value of $\frac{20}{y} + 20 = 5 (\frac{4}{y} + 4)$
Given $\frac{4}{y} + 4 = 5 (\frac{4}{y} + 4)$
Given one is possible only when the value of $\frac{4}{y} + 4 = 0$

Suggest Corrections

Similar questions

Q. Find the value of x and y respectively.
5

\frac{1}{x}

\times y

\frac{3}{4}

= 20

Q. Minimum value of

Z = x - 5 y + 20

under the given conditions

x - y \geq 0 - x + 2 y \geq 2 x \geq 3, y \leq 4 x, y \geq 0

Q. If the shortest distance betwen the lines

\frac{x}{- 2} = \frac{y - 3}{2} = \frac{z - 4}{4}

and

\frac{x - 2}{- 1} = \frac{y + 2}{1} = \frac{z + 4}{2}

d,

then the value of

(6 d^{2} - 20) =

Q. The value of

y = 2 + \frac{1}{4 + \frac{1}{4 + \frac{1}{4 + \frac{1}{4 + . . . . . . \infty}}}}

Find the equation to the circle which passes through the origin and has its center on the line $x + y + 4 = 0$ and cuts the circle $x^{2} + y^{2} - 4 x + 2 y + 4 = 0$ orthogonally.

Join BYJU'S Learning Program

Find the value of 4y+4 given that 4y+4=20y+20

The correct option is A 0The value of 20y+20=5(4y+4)Given 4y+4=5(4y+4)Given one is possible only when the value of 4y+4=0

Find the value of $\frac{4}{y} + 4$ given that $\frac{4}{y} + 4 = \frac{20}{y} + 20$

The correct option is A $0$
The value of $\frac{20}{y} + 20 = 5 (\frac{4}{y} + 4)$
Given $\frac{4}{y} + 4 = 5 (\frac{4}{y} + 4)$
Given one is possible only when the value of $\frac{4}{y} + 4 = 0$