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Question

Find the value of cosAsinA+1cosA+sinA1(cosecA+cotA)

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Solution

Now,
cosAsinA+1cosA+sinA1(cosecA+cotA)
=(cosAsinA+1)(cosA+sinA+1)(cosA+sinA)2(1)2(cosecA+cotA)
=(cosA+1)2(sin2A)2sinA.cosA(cosecA+cotA)
=(cos2A+2cosA+1)(sin2A)2sinA.cosA(cosecA+cotA) [ Since sin2A+cos2A=1]
=1+cos2A+2cosA2sinA.cosA(cosecA+cotA) [ Since cos2Asin2A=cos2A]
=2cos2A+2cosA2sinA.cosA(cosecA+cotA) [ Since 1+cos2A=2cos2A]
=cotA+cosecA(cotA+cosecA)
=0.

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