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Question

Find the value of a2+a24+a38−16.

A
12a+6a2+a3424
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B
12a+6a2+3a3412
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C
12a+6a2+3a32424
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D
12a+6a2+3a3424
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Solution

The correct option is D 12a+6a2+3a3424
a2+a24+a3816
First find the LCM of denominator, 2,4,8 and 6
So, the LCM of 2,4,6 and 8 is 24
Therefore, 12a+6a2+3a3424

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