Question

Find the value of: $\sqrt[3]{3729}$.

Answer 1

On prime factorising, we get,

$729=\underset{–}{3\times 3\times 3}\times \underset{–}{3\times 3\times 3}=3^3\times 3^3=9^3$.

Then, value of $\sqrt[3]{3729}$ is:

$\sqrt[3]{3729}=\sqrt[3]{39^3}=9$.

Therefore, $9$ is the required solution.