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Question

Find the value of 10k=1(sin2πk11icos2πk11)

A
i
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B
i
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C
1
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D
1
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Solution

The correct option is B i
Let S=10k=1(sin2πk11icos2πk11)

=10k=1(i2sin2πk11icos2πk11)

=i10k=1(cos2πk11+isin2πk11)=i10k=1ei2πk11

=i[10k=0ei2πk111]=i (sum of 11th roots of unity=-1)

=i(01)=i
Ans: B

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