Find the value of $e^{5}$ .

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Solution

we have
$e^{5}$
we know that
$e^{x} = 1 + x + \frac{x^{2}}{2!} + \frac{x^{3}}{3!} + - - -$
$∴ e^{5} = 148.413159$
Hence this is the answer.

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figure (32-E5)

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y^{r} = \frac{n! \cdot^{n + r - 1} C_{r - 1}}{r^{n}}

where

n = 2 r

. If

lim n \to \infty y

is equal to

(\frac{a}{e^{b}})

then value of

a + b

${lim}_{x \to 5} \frac{e^{x} - e^{5}}{x - 5}$

lim x \to 0 \frac{e^{x} - e^{5}}{x - 5}

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Find the value of e5.

we have e5we know thatex=1+x+x22!+x33!+−−−∴e5=148.413159Hence this is the answer.

Find the value of $e^{5}$ .

we have
$e^{5}$
we know that
$e^{x} = 1 + x + \frac{x^{2}}{2!} + \frac{x^{3}}{3!} + - - -$
$∴ e^{5} = 148.413159$
Hence this is the answer.