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Question

Find the value of λ for which the four points with position vectors -j^-k^, 4i^+5j^+λk^, 3i^+9j^+4k^ and -4i^+4j^+4k^ are coplanar.

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Solution

Let A, B, C and D be the given points. Then,AB =(4i^+5j^+λk^)-( 0i^-j-k)=4i^+6j^+(λ+1)k^ AC=(3i^+9j^+4k^)-( 0i^-j^-k^) =3i^+10j^+5k^ AD=(-4i^+4j^+4k^)-(0i^-j^-k^ ) =-4i^+5j^+5k^The given points are coplanar iff vectors AB , AC, AD are coplanar.Now, AB , AC, AD are coplanar.ABACAD=0 46(λ+1)3105-455 =04(50-25)-6 (15+20) + (λ+1)(15+40)=0100-210+55λ+55=055λ = 55 λ =1

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