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Question

Find the value of friction forces between the blocks A and B and between B and ground (Take g=10ms−2)
1087705_470d3555174a401e8350bf807d645f93.JPG

A
90 N, 5 N
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B
5 N, 90 N
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C
5 N, 75 N
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D
0 N, 80 N
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Solution

The correct option is D 0 N, 80 N
Let,
F1= frictional force between 15kg block and ground surface
F2= frictional force between 5kg block and 45kg block surface
N1= Normal reaction on block 15kg block
]N2= normal reaction on block 5kg block
because there is no upward motion
N1=15kg+5kg=20kg
N2=5kg
F (limiting)= μN1=0.6×20kg=0.6×20×10=120N
because ground can friction force can able to oppose 120N if we apply force above 120N they only block starts to move. n this block isn't move.
F1=F
F1=80N (because it is self adjusting force)
because there is no actual relative motion and also there is no impending of relative motion (tendency of relative motion)
hence, there no force acting surfaces between 5kg block and 15kg block
So$$,{F_2} = 0$
Hence,
option (D) is correct answer.

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