Find the value of given expression
2(2√2)(2√5)−(2√3) -3(2√3)(2√5)−(2√2) +
(2√5)(2√3)−(2√2)
22√10
Rationalizing the above expression we get
x=(2(2√2)(2√5)−(2√3)×(2√5+(2√3)(2√5)+(2√3))−(3(2√3)(2√5)−(2√2)×2√5+2√22√5+2√2)+((2√5)(2√3)−(2√2)×(2√3)+(2√2)(2√3)+(2√2))
x=(2(2√2)(2√5)2−(2√3)2×(2√5+(2√3)−(3(2√3)(2√5)2−(2√2)2×2√5+2√2)+((2√5)(2√3)2−(2√2)2×(2√3)+(2√2))
x=2×((2√10+2√6)5−3)−3×((2√15+2√6)5−2)+((2√15+2√10)3−2)
x=2√10+2√6−2√15−2√6+2√15+2√10
x=2×2√10