Question

Find the value of $I_o$ (in A) from the below given circuit.

• A. 30

Answer 1

The correct option is A 30
$I_1=\frac{90}{3+6}=10A$

$V_{6\Omega }=I_1\times 6\Omega =10\times 6=60V$
Apply KVL in open loop,

$V_A=60+I_0-V_B=0$

$\Rightarrow V_A-V_B=60-I_o=V_{AB}$

Now, Apply KVL in loop B,

$4V_{AB}-3\times I_o-I_o\times 1=0$

$\Rightarrow 4(60-I_o)-4I_o=0$

$\Rightarrow 240=8I_o$

$\Rightarrow I_o=30A$