Find the value of k1 and k2 for which →V can be represented as →V=k1→A+k2→B. Where, →V=2i−j , →A=3i−2j and →B=3i+3j.
A
k1=1 and k2=1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
k1=35andk2=12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
k1=−23andk2=25
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
k1=35andk2=115
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is Dk1=35andk2=115 The vector →V can be expressed as→V=k1→A+k2→B 2i−j=k1(3i−2j)+k2(3i+3j) ⇒2i−j=(3k1+3k2)i+(−2k1+3k2)j Equating terms from both sides ⇒2=(3k1+3k2) ⇒−1=(−2k1+3k2) Solving both the equations we get k1=35 and k2=115