Find the value of k for which the point (1, −2) lies on the graph of the linear equation x − 2y + k = 0.

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Solution

We are given lies on the graph of linear equation.

So, the given co-ordinates are the solution of the equation.

Therefore, we can calculate the value of k by substituting the value of given co-ordinates in equation.

Substituting in equation, we get

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Find the value of k for which the point (1, -2) lies on the graph of the linear equation $x - 2 y + k = 0.$

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