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Question

Find the value of k for which the quadratic equation kx^2 + 2x + 1 = 0 has a real and distinct root.

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Solution

The given quadratic equation is,kx2 + 2x + 1 = 0Now, a = k; b = 2; c = 1Now, D = b2 - 4ac=22 - 4 k1=4 - 4kFor real and distinct roots, D > 04 - 4k > 04 > 4k4k <4k < 1

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