Find the value of k if the lines given by 3x+2ky=2 ; 2x+5y=12 are parallel

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Solution

If two lines are parallel,then their slopes are equal

For a straight line with equation ax +by + c = 0,

the slope is given by m = -a/b.

Let the slope of 3x + 2ky = 2 be 'm1′.

Let the slope of 2x + 5y + 1 = 0 be 'm2′.

Slope of 3x + 2ky = 2 is m1 = -3/2k.

Slope of 2x + 5y + 1 = 0 is m2 = -2/5.

Since the two lines are parallel,

m1 = m2. So,

-3/2k = -2/5

3×5 = 2k×2

15 = 4k

=> k = 15/4.

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Similar questions

k

3 x + 2 k y = 2

2 x + 5 y + 1 = 0

3 x + 2 k y = 2

2 x + 5 y + 1 = 0

k

3 x + 2 k y = 2

2 x + 5 y + 1 = 0

k

3 x + 2 k y = 2 and 2 x + 5 y + 1 = 0

\frac{- 5}{4}

\frac{2}{5}

\frac{3}{2}

\frac{15}{4}

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