Question

Find the value of k, if (x-1) is a factor of $2x^2+kx+\sqrt{2}$

Answer 1

if $x-1$ is a factor of given $e{q}^n$ then it

will satisfy this $e{q}^n$ ,$x-1=0,x=1kx,$

$2x^2+kx+\sqrt{2}$

$2+k+\sqrt{2}=0$

$k=-(\sqrt{2}+2)$