Question

Find the value of $k,$ if $x=2,y=1$ is a solution of the equation $2x+3y=k$. Find two more solutions of the resultant equation.

Answer 1

Given equation, $2x+3y=k$

$x=2,y=1$ is solution of resultant equation.

$2\left(2\right)+3\left(1\right)=k$

$\therefore k=7$

$\therefore$ Resultant equation is $2x+3y=7$

At $x=0,2\left(0\right)+3y=7$

$y=\frac{7}{3}$

At $y=0,2x+3\left(0\right)=7$

$x=\frac{7}{2}$

$\therefore (x=0,y=\frac{7}{3}$) and ($x=\frac{7}{2},y=0$) are two more solutions of resultant equations.