Question

Find the value of
${\left(\frac{1}{2}\right)}^{-2}+{\left(\frac{1}{3}\right)}^{-2}+{\left(\frac{1}{4}\right)}^{-2}$

Answer 1

${\left(\frac{1}{2}\right)}^{-2}+{\left(\frac{1}{3}\right)}^{-2}+\left({\left(\frac{1}{4}\right)}^{-2}\right)={\left(2\right)}^2+{\left(3\right)}^2+{\left(4\right)}^2=4+9+16=13+16=29$