Find the value of limh→ 0[2−h]+limh→ 0[2+h]
As we saw in the previous question [2-h], when h tends h tends to zero is 1 and [2+h] is 2.
⇒limh→ 0[2−h]+limh→ 0[2+h]=limh→ 01+limh→ 02
=1+2
=3
limh→0√x+h−√xh,x≠0