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Question

Find the value of m and n using cross multiplication method:
3m+n=15 and m+2n=10.

A
(4, 3)
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B
(-4, 3)
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C
(-4, -3)
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D
(4, -3)
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Solution

The correct option is A (4, 3)
3m+n=15 ----- (1)
m+2n=10 ----- (2)
First use formula for cross multiplication method:
mb1c2b2c1=nc1a2a1c2=1a2b2a2b1
So, from equation (1) and (2) we can write the value of a, b and c.
m1×102×15=n15×13×10=13×21×1
m1030=n1530=161
m20=n15=15
m20=15
m=205=4
n15=15
n=155=3
The solution is (4, 3)

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