Question

Find the value of $n$

$\frac{\frac{n}{4}-\frac{3}{5}}{\frac{4}{3}-7n}=\frac{3}{20}$

• A. $\frac{8}{3}$
• B. $\frac{8}{13}$
• C. $\frac{6}{13}$
• D. None of these

Answer 1

Answer: (B)

$\frac{8}{13}$

$\frac{\frac{n}{4}-\frac{3}{5}}{\frac{4}{3}-7n}=\frac{3}{20}$

$⟹\frac{\left(\frac{5n-12}{20}\right)}{\left(\frac{4-21n}{3}\right)}=\frac{3}{20}$

$⟹20\times \left(\frac{5n-12}{20}\right)=3\times \left(\frac{4-21n}{3}\right)$

$⟹5n-12=4-21n$

$⟹5n+21n=4+12$

$⟹26n=16$

$⟹n=\frac{16}{26}$

$\therefore n=\frac{8}{13}$