Find the value of n such that $2 (4 n - 1) - 1 (5 n - 1) = n + 5$

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Solution

The correct option is D
3

$2 (4 n - 1) - 1 (5 n - 1) = n + 5$
$8 n - 2 - 5 n + 1 = n + 5$
$(8 n - 5 n) + (- 2 + 1) = n + 5$
$3 n - 1 = n + 5$
$3 n - n = 5 + 1$
$2 n = 6$
$n = 3$ .

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