$Solve for n:$
$2 (4 n - 1) - 1 (5 n - 1) = n + 4$

- $\frac{5}{4}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{5}{4}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- $\frac{5}{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{5}{2}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
$\frac{5}{2}$

Given,
$2 (4 n - 1) - 1 (5 n - 1) = n + 4$
$\Rightarrow 8 n - 2 - 5 n + 1 = n + 4$
$\Rightarrow (8 n - 5 n) + (- 2 + 1) = n + 4$
$\Rightarrow 3 n - 1 = n + 4$

Transposing $n$ from RHS to LHS and $- 1$ from LHS to RHS, we get,
$\Rightarrow 3 n - n = 4 + 1$
$\Rightarrow 2 n = 5$
$\Rightarrow n = \frac{5}{2}$

Suggest Corrections

Similar questions

n \in N, 2^{4 n} - 15 n - 1

Find the value of n such that $2 (4 n - 1) - 1 (5 n - 1) = n + 5$

Show that $2^{4 n + 4} - 15 n - 16$ , where $n \in N$ is divisible by 225.

2^{4 n + 4} - 15 n - 16

ℕ

2^{4 n + 4} - 15 n - 16, n \in N

225

Join BYJU'S Learning Program