Find the value of n such that-2-34n-3 - 2n-1-n-3-1-3n-4-3

Given expression, 2/3(4n 3) ( 2n 1+n/3)=1/3n+5/3 2/3(4n 3) 1/3(6n 1 n) nbsp;=1/3n+5/3 The denominator of all the terms are same. nbsp;So, by removing th ...

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Standard XII

Mathematics

Sum of n Terms

Find the valu...

Question

Find the value of $n$ such that:
$\frac{2}{3} (4 n - 3) - (2 n - \frac{1 + n}{3}) = \frac{1}{3} n + \frac{4}{3}$

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Solution

The correct option is B 5
Given expression,
$\frac{2}{3} (4 n - 3) - (2 n - \frac{1 + n}{3}) = \frac{1}{3} n + \frac{5}{3}$

$⟹ \frac{2}{3} (4 n - 3) - \frac{1}{3} (6 n - 1 - n) = \frac{1}{3} n + \frac{5}{3}$

The denominator of all the terms are same. So, by removing the denominator,

$2 (4 n - 3) - (5 n - 1) = n + 5$

$⟹ 8 n - 6 - 5 n + 1 = n + 5$

$⟹ 3 n - 5 = n + 5$

$⟹ 3 n - n = 5 + 5$

$⟹ 2 n = 10$

$⟹ n = 5$

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Find the value of n such that $\frac{2}{3} (4 n - 1) - (2 n - \frac{1 + n}{3}) = \frac{1}{3} n + \frac{4}{3}$ .

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Find the value of n such that: 23(4n−3)−(2n−1+n3)=13n+43

The correct option is B 5Given expression, 23(4n−3)−(2n−1+n3)=13n+53 ⟹23(4n−3)−13(6n−1−n)=13n+53 The denominator of all the terms are same. So, by removing the denominator, 2(4n−3)−(5n−1)=n+5 ⟹8n−6−5n+1=n+5 ⟹3n−5=n+5 ⟹3n−n=5+5 ⟹2n=10 ⟹n=5

Find the value of $n$ such that:
$\frac{2}{3} (4 n - 3) - (2 n - \frac{1 + n}{3}) = \frac{1}{3} n + \frac{4}{3}$