Find the value of ‘p’ for which the lines 2 + 3y – 7 = 0 & 4y + – 12 = 0 are ⊥ to each other.

p = 6

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p = 8

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p = -8

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p = -6

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p = 7

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Solution

The correct option is D
p = -6

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Similar questions

Find the value of P for which the lines 2x + 3y -7 = 0 and 4y - px - 12 = 0 are perpendicular to each other.

If the lines y = 3 + 7 & 2y + p = 3 are || to each other, find the value of p.

2 x + 3 y - 7 = 0

4 y - p x - 12 = 0

Find the value of ‘p’ for which the quadratic equations have equal roots.

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(2)

(3)

(4)

(5)

(6)

3 x + 4 y - 5 = 0, 2 x + 3 y - 4 = 0, p x + 4 y - 6

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