Find the value of polynomial $P (x) = x^{2} - 2 x + 5$ for $x = - 1$ and $x = 5$ .

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Solution

Given: $P (x) = x^{2} - 2 x + 5$
For $x = - 1,$ $P (- 1) = (- 1)^{2} - 2 (- 1) + 5 = 1 + 2 + 5 = 8$
For $x = 5,$ $P (5) = (5)^{2} - 2 (5) + 5 = 25 - 10 + 5 = 20$
Hence $P (- 1) = 8$ and $P (5) = 20$

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